Integrand size = 24, antiderivative size = 564 \[ \int \frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{(f+g x)^4} \, dx=\frac {b^2 e^2 n^2 (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )}{(e f-d g)^3 (f+g x)}+\frac {b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{2 g (e f-d g) (f+g x)^2}-\frac {b e^2 n (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{(e f-d g)^3 (f+g x)}-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{3 g (f+g x)^3}-\frac {b^3 e^3 n^3 \log (f+g x)}{g (e f-d g)^3}+\frac {2 b^2 e^3 n^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (f+g x)}{e f-d g}\right )}{g (e f-d g)^3}+\frac {b^2 e^3 n^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (1+\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}-\frac {b e^3 n \left (a+b \log \left (c (d+e x)^n\right )\right )^2 \log \left (1+\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}-\frac {b^3 e^3 n^3 \operatorname {PolyLog}\left (2,-\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}+\frac {2 b^2 e^3 n^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \operatorname {PolyLog}\left (2,-\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}+\frac {2 b^3 e^3 n^3 \operatorname {PolyLog}\left (2,-\frac {g (d+e x)}{e f-d g}\right )}{g (e f-d g)^3}+\frac {2 b^3 e^3 n^3 \operatorname {PolyLog}\left (3,-\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3} \]
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Time = 0.69 (sec) , antiderivative size = 564, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {2445, 2458, 2389, 2379, 2421, 6724, 2355, 2354, 2438, 2356, 2351, 31} \[ \int \frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{(f+g x)^4} \, dx=\frac {2 b^2 e^3 n^2 \operatorname {PolyLog}\left (2,-\frac {e f-d g}{g (d+e x)}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{g (e f-d g)^3}+\frac {2 b^2 e^3 n^2 \log \left (\frac {e (f+g x)}{e f-d g}\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{g (e f-d g)^3}+\frac {b^2 e^3 n^2 \log \left (\frac {e f-d g}{g (d+e x)}+1\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )}{g (e f-d g)^3}+\frac {b^2 e^2 n^2 (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )}{(f+g x) (e f-d g)^3}-\frac {b e^3 n \log \left (\frac {e f-d g}{g (d+e x)}+1\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{g (e f-d g)^3}-\frac {b e^2 n (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{(f+g x) (e f-d g)^3}+\frac {b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{2 g (f+g x)^2 (e f-d g)}-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{3 g (f+g x)^3}-\frac {b^3 e^3 n^3 \operatorname {PolyLog}\left (2,-\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}+\frac {2 b^3 e^3 n^3 \operatorname {PolyLog}\left (2,-\frac {g (d+e x)}{e f-d g}\right )}{g (e f-d g)^3}+\frac {2 b^3 e^3 n^3 \operatorname {PolyLog}\left (3,-\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}-\frac {b^3 e^3 n^3 \log (f+g x)}{g (e f-d g)^3} \]
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Rule 31
Rule 2351
Rule 2354
Rule 2355
Rule 2356
Rule 2379
Rule 2389
Rule 2421
Rule 2438
Rule 2445
Rule 2458
Rule 6724
Rubi steps \begin{align*} \text {integral}& = -\frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{3 g (f+g x)^3}+\frac {(b e n) \int \frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^2}{(d+e x) (f+g x)^3} \, dx}{g} \\ & = -\frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{3 g (f+g x)^3}+\frac {(b n) \text {Subst}\left (\int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x \left (\frac {e f-d g}{e}+\frac {g x}{e}\right )^3} \, dx,x,d+e x\right )}{g} \\ & = -\frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{3 g (f+g x)^3}-\frac {(b n) \text {Subst}\left (\int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{\left (\frac {e f-d g}{e}+\frac {g x}{e}\right )^3} \, dx,x,d+e x\right )}{e f-d g}+\frac {(b e n) \text {Subst}\left (\int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x \left (\frac {e f-d g}{e}+\frac {g x}{e}\right )^2} \, dx,x,d+e x\right )}{g (e f-d g)} \\ & = \frac {b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{2 g (e f-d g) (f+g x)^2}-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{3 g (f+g x)^3}-\frac {(b e n) \text {Subst}\left (\int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{\left (\frac {e f-d g}{e}+\frac {g x}{e}\right )^2} \, dx,x,d+e x\right )}{(e f-d g)^2}+\frac {\left (b e^2 n\right ) \text {Subst}\left (\int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x \left (\frac {e f-d g}{e}+\frac {g x}{e}\right )} \, dx,x,d+e x\right )}{g (e f-d g)^2}-\frac {\left (b^2 e n^2\right ) \text {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{x \left (\frac {e f-d g}{e}+\frac {g x}{e}\right )^2} \, dx,x,d+e x\right )}{g (e f-d g)} \\ & = \frac {b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{2 g (e f-d g) (f+g x)^2}-\frac {b e^2 n (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{(e f-d g)^3 (f+g x)}-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{3 g (f+g x)^3}-\frac {b e^3 n \left (a+b \log \left (c (d+e x)^n\right )\right )^2 \log \left (1+\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}+\frac {\left (2 b^2 e^2 n^2\right ) \text {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{\frac {e f-d g}{e}+\frac {g x}{e}} \, dx,x,d+e x\right )}{(e f-d g)^3}+\frac {\left (2 b^2 e^3 n^2\right ) \text {Subst}\left (\int \frac {\log \left (1+\frac {e f-d g}{g x}\right ) \left (a+b \log \left (c x^n\right )\right )}{x} \, dx,x,d+e x\right )}{g (e f-d g)^3}+\frac {\left (b^2 e n^2\right ) \text {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{\left (\frac {e f-d g}{e}+\frac {g x}{e}\right )^2} \, dx,x,d+e x\right )}{(e f-d g)^2}-\frac {\left (b^2 e^2 n^2\right ) \text {Subst}\left (\int \frac {a+b \log \left (c x^n\right )}{x \left (\frac {e f-d g}{e}+\frac {g x}{e}\right )} \, dx,x,d+e x\right )}{g (e f-d g)^2} \\ & = \frac {b^2 e^2 n^2 (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )}{(e f-d g)^3 (f+g x)}+\frac {b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{2 g (e f-d g) (f+g x)^2}-\frac {b e^2 n (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{(e f-d g)^3 (f+g x)}-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{3 g (f+g x)^3}+\frac {2 b^2 e^3 n^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (f+g x)}{e f-d g}\right )}{g (e f-d g)^3}+\frac {b^2 e^3 n^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (1+\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}-\frac {b e^3 n \left (a+b \log \left (c (d+e x)^n\right )\right )^2 \log \left (1+\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}+\frac {2 b^2 e^3 n^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \text {Li}_2\left (-\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}-\frac {\left (b^3 e^2 n^3\right ) \text {Subst}\left (\int \frac {1}{\frac {e f-d g}{e}+\frac {g x}{e}} \, dx,x,d+e x\right )}{(e f-d g)^3}-\frac {\left (b^3 e^3 n^3\right ) \text {Subst}\left (\int \frac {\log \left (1+\frac {e f-d g}{g x}\right )}{x} \, dx,x,d+e x\right )}{g (e f-d g)^3}-\frac {\left (2 b^3 e^3 n^3\right ) \text {Subst}\left (\int \frac {\log \left (1+\frac {g x}{e f-d g}\right )}{x} \, dx,x,d+e x\right )}{g (e f-d g)^3}-\frac {\left (2 b^3 e^3 n^3\right ) \text {Subst}\left (\int \frac {\text {Li}_2\left (-\frac {e f-d g}{g x}\right )}{x} \, dx,x,d+e x\right )}{g (e f-d g)^3} \\ & = \frac {b^2 e^2 n^2 (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )}{(e f-d g)^3 (f+g x)}+\frac {b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{2 g (e f-d g) (f+g x)^2}-\frac {b e^2 n (d+e x) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{(e f-d g)^3 (f+g x)}-\frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{3 g (f+g x)^3}-\frac {b^3 e^3 n^3 \log (f+g x)}{g (e f-d g)^3}+\frac {2 b^2 e^3 n^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (\frac {e (f+g x)}{e f-d g}\right )}{g (e f-d g)^3}+\frac {b^2 e^3 n^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \log \left (1+\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}-\frac {b e^3 n \left (a+b \log \left (c (d+e x)^n\right )\right )^2 \log \left (1+\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}-\frac {b^3 e^3 n^3 \text {Li}_2\left (-\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}+\frac {2 b^2 e^3 n^2 \left (a+b \log \left (c (d+e x)^n\right )\right ) \text {Li}_2\left (-\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3}+\frac {2 b^3 e^3 n^3 \text {Li}_2\left (-\frac {g (d+e x)}{e f-d g}\right )}{g (e f-d g)^3}+\frac {2 b^3 e^3 n^3 \text {Li}_3\left (-\frac {e f-d g}{g (d+e x)}\right )}{g (e f-d g)^3} \\ \end{align*}
Time = 0.71 (sec) , antiderivative size = 843, normalized size of antiderivative = 1.49 \[ \int \frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{(f+g x)^4} \, dx=\frac {3 b e (e f-d g)^2 n (f+g x) \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^2+6 b e^2 (e f-d g) n (f+g x)^2 \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^2-6 b (e f-d g)^3 n \log (d+e x) \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^2+6 b e^3 n (f+g x)^3 \log (d+e x) \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^2-2 (e f-d g)^3 \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^3-6 b e^3 n (f+g x)^3 \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^2 \log (f+g x)+6 b^2 n^2 \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right ) \left (e^2 g (d+e x) (f+g x)^2+g \left (3 d e^2 f^2-3 d^2 e f g+d^3 g^2+e^3 x \left (3 f^2+3 f g x+g^2 x^2\right )\right ) \log ^2(d+e x)+3 e^3 (f+g x)^3 \log \left (\frac {e (f+g x)}{e f-d g}\right )+e (f+g x) \log (d+e x) \left (g^2 (d+e x)^2-4 e g (d+e x) (f+g x)-2 e^2 (f+g x)^2 \log \left (\frac {e (f+g x)}{e f-d g}\right )\right )-2 e^3 (f+g x)^3 \operatorname {PolyLog}\left (2,\frac {g (d+e x)}{-e f+d g}\right )\right )+b^3 n^3 \left (2 g \left (3 d e^2 f^2-3 d^2 e f g+d^3 g^2+e^3 x \left (3 f^2+3 f g x+g^2 x^2\right )\right ) \log ^3(d+e x)-6 e^3 (f+g x)^3 \log \left (\frac {e (f+g x)}{e f-d g}\right )+3 e (f+g x) \log ^2(d+e x) \left (g^2 (d+e x)^2-4 e g (d+e x) (f+g x)-2 e^2 (f+g x)^2 \log \left (\frac {e (f+g x)}{e f-d g}\right )\right )+18 e^3 (f+g x)^3 \operatorname {PolyLog}\left (2,\frac {g (d+e x)}{-e f+d g}\right )+6 e^2 (f+g x)^2 \log (d+e x) \left (g (d+e x)+3 e (f+g x) \log \left (\frac {e (f+g x)}{e f-d g}\right )-2 e (f+g x) \operatorname {PolyLog}\left (2,\frac {g (d+e x)}{-e f+d g}\right )\right )+12 e^3 (f+g x)^3 \operatorname {PolyLog}\left (3,\frac {g (d+e x)}{-e f+d g}\right )\right )}{6 g (e f-d g)^3 (f+g x)^3} \]
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\[\int \frac {{\left (a +b \ln \left (c \left (e x +d \right )^{n}\right )\right )}^{3}}{\left (g x +f \right )^{4}}d x\]
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\[ \int \frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{(f+g x)^4} \, dx=\int { \frac {{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )}^{3}}{{\left (g x + f\right )}^{4}} \,d x } \]
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\[ \int \frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{(f+g x)^4} \, dx=\int \frac {\left (a + b \log {\left (c \left (d + e x\right )^{n} \right )}\right )^{3}}{\left (f + g x\right )^{4}}\, dx \]
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\[ \int \frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{(f+g x)^4} \, dx=\int { \frac {{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )}^{3}}{{\left (g x + f\right )}^{4}} \,d x } \]
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\[ \int \frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{(f+g x)^4} \, dx=\int { \frac {{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )}^{3}}{{\left (g x + f\right )}^{4}} \,d x } \]
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Timed out. \[ \int \frac {\left (a+b \log \left (c (d+e x)^n\right )\right )^3}{(f+g x)^4} \, dx=\int \frac {{\left (a+b\,\ln \left (c\,{\left (d+e\,x\right )}^n\right )\right )}^3}{{\left (f+g\,x\right )}^4} \,d x \]
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